carilah akar akar persamaan kuadrat x2 - x - 42 = 0
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Penjelasan dengan langkah-langkah:
x² - x - 42 = 0
x² - x = 42
(x - 1/2)² - 1/4 = 42
(x - 1/2)² = 42 + 1/4
(x + 1/2)² = 168/4 + 1/4
(x + 1/2)² = 169/4
x + 1/2 = ±√169/4
x + 1/2 = ±13/2
x = -1/2 ± 13/2
x1 = -1/2 + 13/2 = 12/2 = 6
x2 = -1/2 - 13/2 = -14/2 = -7
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